PROCEDIMIENTO DE LA TAREA 1

Jorge mauro cazares Godínez. Turno. Matutino 1-5
1) procedimiento que me faltaba dela tarea 1.
1) (3) (2)=6(-5)=-30(2)-60(3)-180(-7)=1260(8)=10080
2) (5)(-5)(3)+2+4-7-12+45-33+75=-25(3)=-75
-13+35=32-33=-1+75=74-75=-1
3)-146+13=-133+54=-79-65=-144+67=(-77)(-24)=1848
4)-32+36=4-76=-72+89=17-55=-38+243=205-74=131
5) (6)(-4)=-24(5)=-120(-6)=720(7)=5040(-8)=-40320(9)=-362880(0)=0
6)72/15+32/99=7608/1485=2536/495
7) 14/3+15/2=73/6-6/4=256/24=32/3
8) (180/20)/ (208/63)=2268/1120
9)559/330-16/7=-1367/2310
10) (72/48)/(25/4)=702000/108000-16/4=1080000/432000
11)3/5-18/7=-69/35=1485/204-69/35=37899/7140+29/9=548151/64260=2